(x^2+4x+2)(5x^2-4)=0

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Solution for (x^2+4x+2)(5x^2-4)=0 equation: 


Simplifying
(x2 + 4x + 2)(5x2 + -4) = 0

Reorder the terms:
(2 + 4x + x2)(5x2 + -4) = 0

Reorder the terms:
(2 + 4x + x2)(-4 + 5x2) = 0

Multiply (2 + 4x + x2) * (-4 + 5x2)
(2(-4 + 5x2) + 4x * (-4 + 5x2) + x2(-4 + 5x2)) = 0
((-4 * 2 + 5x2 * 2) + 4x * (-4 + 5x2) + x2(-4 + 5x2)) = 0
((-8 + 10x2) + 4x * (-4 + 5x2) + x2(-4 + 5x2)) = 0
(-8 + 10x2 + (-4 * 4x + 5x2 * 4x) + x2(-4 + 5x2)) = 0
(-8 + 10x2 + (-16x + 20x3) + x2(-4 + 5x2)) = 0
(-8 + 10x2 + -16x + 20x3 + (-4 * x2 + 5x2 * x2)) = 0
(-8 + 10x2 + -16x + 20x3 + (-4x2 + 5x4)) = 0

Reorder the terms:
(-8 + -16x + 10x2 + -4x2 + 20x3 + 5x4) = 0

Combine like terms: 10x2 + -4x2 = 6x2
(-8 + -16x + 6x2 + 20x3 + 5x4) = 0

Solving
-8 + -16x + 6x2 + 20x3 + 5x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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